3x^2+5=330

Solution for 3x^2+5=330 equation:

3x^2+5=330

We move all terms to the left:

3x^2+5-(330)=0

We add all the numbers together, and all the variables

3x^2-325=0

a = 3; b = 0; c = -325;
Δ = b2-4ac
Δ = 02-4·3·(-325)
Δ = 3900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3900}=\sqrt{100*39}=\sqrt{100}*\sqrt{39}=10\sqrt{39}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{39}}{2*3}=\frac{0-10\sqrt{39}}{6}
=-\frac{10\sqrt{39}}{6}
=-\frac{5\sqrt{39}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{39}}{2*3}=\frac{0+10\sqrt{39}}{6}
=\frac{10\sqrt{39}}{6}
=\frac{5\sqrt{39}}{3}
$